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A flywheel is revolving at 150 revolutions per minutes .If deccelerates at a constant rate of `2 pi rad //s^(2)`, then time requred to stop it isA. `10 s`B. `5 s`C. `2.5 s`D. `1.25 s` |
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Answer» Correct Answer - C `alpha =(omega_(2)-omega_(1))/(t)" "therefore t=(5pi)/(2pi)=2.5sec`. |
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