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A flywheel rotating at a speed of `600` rpm about its axis is brought to rest by applying a constant torque for `10` seconds. Find the angular deceleration and angular velocity `5` second after the application of the torque. |
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Answer» Correct Answer - A::B A wheel rotating at a speed of 600 rpm `omega_0=600 rpm` =10 revolutions per second r=10sec (in 10 sec it comes to rest) omega=0` therefore `omega_0=-at` `rarr a=-10/10=-`rev/s^2` rarr omega=omega_0+at` `=10-1xx5=5rev/s` Therefore angular deceleration `=1rev/s^2 and Angular velocity after 5 sec is 5 rev/s. |
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