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A flywheel with moment of inertia 0.86 kg ·m^2and a cylinder of 5 cm radius of negligible mass are fixed to a common shaft (Fig.). A thread is wound around the cylinder, and a weight of 6.0 kg mass is attached to it. What time will the weight take to fall 1 m? What will be its final speed? Assume the initial speed to be zero. |
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Answer» `mgh=1/2mv^2+1/2Iomega^2` The flywheel and the cylinder ROTATE at the same angular VELOCITY `omega = v//r` , therefore `2mgh = v^2 (m + 1//r^2)`. Hence `v=sqrt((2mgh)/(m+I//r^2)` |
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