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A foce acts on a 30.g particle in such a way that the position of the particle as a function of time is given by `x=3t-4t^(2)+t^(3)`, where x is in metre and t in second. The work done during the first 4s isA. 5.28 JB. 450 mJC. 490 mJD. 530 mJ |
Answer» Correct Answer - A |
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