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a) For the telescope described in Exercise 34 (a), what is the separation between the objective lens and the eyepiece ? |
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Answer» SOLUTION :(a) `f_(O)+f_(e)=145cm` (b) Angled subtended by the TOWER `=(100//3000)=(1//30)`rad Angled subtended by the image produced by the OBJECTIVE `=(h)/(f_(O))=(h)/(140)` Equating the two, `h=4.7cm`. (c) Magnification (magnitude) of the eye-piece = 6. Height of the final image (magnitude) = 28 cm. |
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