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A force F=-10x+2 acts on a particle of mass 0.1 kg where m is m and F is in newtons. If F is released from rest at x=0, find: a. amplitude: b. time period: c. equation of motion. |
Answer» Correct Answer - `(11)/(5)m,(b)(pi)/(5)sec.,(c )X=0.2-(11)/(5)cosomegat` | |