InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A force `F=(2+x)` acts on a particle in x-direction where F is in newton and x in metre. Find the work done by this force during a displacement form 1. 0 m to x = 2.0 m. |
|
Answer» Correct Answer - C As the force is variable, we shall find the work done in a small dispacent from x to x + dx and then intrgrate it to find the total work done in thes small displacement is. `dW=F dx=(2+x)dx` Thus, `W=int_(2.0)^(1.0)dW = int_(1.0)^(2.0)(2+x)dx` `=[2xxx2/2]_(1.0)^(2.0)=3.5J`. |
|