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A force `F=2x+3x^2`N acts on a particle in the x-direction. Find the work done by this force during a displacement `x=1.0m ` to `x=2.0m` |
Answer» Here force is variable `W=int_(x1)^(x2)Fdx=int_1^2(2x+3x^2)dx` `=2.(x^2)/(2)+3(x^3)/(3)=|x^2+x^3|_1^2` `={(2)^2+(2)^3}-{1^2+1^3}=12-2=10J` |
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