InterviewSolution
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InterviewSolution
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A force `F=(5+2x)` acts on a particle in x direction where F is in newtown and x is meter. Find the work done by this force during displacement from `x=0` to `x=1m.` |
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Answer» `F=(5+2x)` `dW=vecF.vec(dx)=(5+2x)dx` Total work done,` W=underset(x=0)overset(x=1)int(5+2x)dx` `F=(5+2x)` `dW=vecF.vec(dx)=(5+2x)dx` `W=[5x+2.(x^(2))/(2)]_(0)^(1)` `=5(1-0)+(1^(2)-0)=6J` |
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