1.

A Force `F` acting on an object varies with distance `x` as shown in the here . The force is in newton and `x` in metre. The work done by the force in moving the object from `x = 0` to `x = 6m` is A. `4.5 J`B. `13.5 J`C. `9.0 J`D. `18.0 J`

Answer» Work done = Area enclosed by `F - x` graph
` = (1)/(2) xx (3 +6) xx 3 = 13.5 J`


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