A force F of constant magnitude acts on a block of mass 'm' and t=0,initially along positive x-direction. The direction of force F starts rotating with a constant angular velocity omega in anticlockwise sense. Then the magnitude of velocity of the block as a function of time 't' is ( initial block was at rest )

A force F of constant magnitude acts on a block of mass 'm' and t=0,in

1.	A force F of constant magnitude acts on a block of mass 'm' and t=0,initially along positive x-direction. The direction of force F starts rotating with a constant angular velocity omega in anticlockwise sense. Then the magnitude of velocity of the block as a function of time 't' is ( initial block was at rest )
Answer» `(F)/( m OMEGA ) SIN ((omegat)/( 2))` `(2F)/( m omega ) sin ((omegat)/( 2))` `(F)/( 2 m omega) sin ((omegat)/( 2))` `(2F)/( 3 m omega) sin ((omegat)/( 2))` Answer :B

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