InterviewSolution
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InterviewSolution
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A force given by the relation `F=8t`, acts on a body of mass `2 kg`, initialiy at rest. Find the work done by this force on the body during first `2` seconds of its motion.A. `64J`B. zeroC. `-64J`D. none of these |
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Answer» `F=3t` `m.(dv)/(dt)=8t` `m int_(0)^(v)dv=8 int_(0)^(t) dt` `mv=4t^(2)` or `m(dx)/(dt)=4t^(2)rArrdx=(4t^(2))/(m)dt=2t^(2)dt` `W=intFdx=int_(0)^(2)(8txx2t^(2))dt=64J` |
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