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A force is inclined at `60^(@)` to the horozontal. If its rectangular component in the horizontal direction is `50 N`, then magnitude of the verticle components of force is approximatelyA. `25 N`B. `84 N`C. `87 N`D. `90 N` |
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Answer» Correct Answer - C `R_(x)= 50 = R cos 60^(@) impliesR= 100 N` `R_(y)= R sin 60^(@)= (100 sqrt(3))/(2)= 50 sqrt(3) N` `=86.6 N` ~~ 87 N` |
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