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A force vecF=(5hati+3hatj+2hatk)N is applied over a particle which displaces it from its origin to the point vecr=(2hati-hatj) m. The work done on the particle in joules is : |
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Answer» SOLUTION :Here, `W=vecF.vecS` =`(5hati+3hatj+2hatk).(2hati-hatj)` =10-3=7 J. |
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