1.

A force vecF=(5hati+3hatj+2hatk)N is applied over a particle which displaces it from its origin to the point vecr=(2hati-hatj) m. The work done on the particle in joules is :

Answer»

-7
`+7`
`+10`
`+13`

SOLUTION :Here, `W=vecF.vecS`
=`(5hati+3hatj+2hatk).(2hati-hatj)`
=10-3=7 J.


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