1.

A force vector applied on a mass is represented by vec(F)=6hati + 8hatj+10hatk and it accelerates it with 1 ms^(-1) . What will be the mass of the body ?

Answer»

`10sqrt(2)` kg
`2sqrt(10)` kg
10 kg
20 kg

Solution :Here magnitude of the FORCE acting
`|vec(F)\=[6^(2)+8^(2)+10^(2)]^(1//2)=(200)^(1//2)`
`m=|vec(F)|/|a|=(200)^(2)/1=10sqrt(2)kg`


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