A force of 10 N is applied on 2 bodies of masses m1 and m2 in order to accelerate them at 2 m/s² and 4 m/s² .Required to find :-Acceleration of the bodies when they are tied to together ?Formula used :-\boxed{\tt{mass = \frac{force}{acceleration} }} mass= accelerationforce Solution :-Given information :-A force of 10 N is applied on 2 bodies of masses m1 and m2 in order to accelerate them at 2 m/s² and 4 m/s² .From the given information we can CONCLUDE that ;Case - 1Force ( F1 ) = 10 NAcceleration ( a1 ) = 2 m/s²Case - 2Force ( F2 ) = 10 NAcceleration ( a2 ) = 4 m/s²We need to find the masses of the respective bodies in 2 casesSo,In case - 1Force ( F1 ) = 10 NAcceleration ( a1 ) = 2 m/s²Using the formula,\boxed{\tt{Mass = \dfrac{Force}{Acceleration} }} Mass= AccelerationForce ARROW{\tt{ Mass = \dfrac{ 10 }{ 2 } }}arrowMass= 210 arrow{\tt{ {M}_{1} = 5 \ kg }}arrowM 1 =5 kgSimilarly,In case - 2Force ( F2 ) = 10 NAcceleration ( a2 ) = 4 m/s²Using the same formula,arrow{\tt{ Mass = \dfrac{ 10}{ 4 } }}arrowMass= 410 arrow{\tt{ {M}_{2} = 2.5 }}arrowM 2 =2.5Now,we need to find the acceleration when the two bodies are tied together ;This means that we need to divide the Force by sum of the masses of two bodies ( Total Mass ) .Hence,Total mass = m1 + m2=> 5 + 2.5=> 7.5 kgHowever,\tt{ Acceleration = \dfrac{ 10 }{ 7.5 } }Acceleration= 7.510 Multiply the numerator and denominator with 10So,\tt{ Acceleration = \dfrac{ 10 \times 10 }{ 7.5 \times 10 } }Acceleration= 7.5×1010×10 \tt{ Acceleration = \dfrac{ 100 }{ 75 }}Acceleration= 75100 \tt{ Acceleration = 1.333 \dots }Acceleration=1.333…\implies{\UNDERLINE{\rm{ Acceleration = 1.33 \ m/s^2 \; ( approximately ) }}}⟹ Acceleration=1.33 m/s 2 (approximately) Therefore,Acceleration caused when two bodies are tied together = 1.33 m/s² ( approximately )Explanation:MARK ME AS BRAINLIST