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A fork A has frequency 2% more than the standard fork and B has a frequency 3% less than the frequency of same standard fork. The forks A and B when sounded together produced 6 beats s^(-1) . The frequency of fork A is |
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Answer» 116.4 Hz the frequency of B, `upsilon_B=upsilon-3/100upsilon` According to QUESTION , `upsilon_A-upsilon_B=6` `therefore (upsilon+ 2/100upsilon)-(upsilon-3/100upsilon)=6` `5/100 upsilon =6` or `upsilon=600/5`=120 Hz The frequency of A `upsilon_A=(upsilon + 2/100upsilon)=120+ 2/100 XX 120` = 122.4 Hz |
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