1.

A fork gives 5 beats with a 40 cm length of sonometre wire. If the length of the wire is shortened by 1 cm, the number of beats is still the same. The frequency of the fork is :

Answer»

385 Hz
600 Hz
395 Hz
400 Hz

Solution :Here v = `(1)/(2l)sqrt(T//m)`
`THEREFORE "" v l ` = constant
`therefore"" v_(1) l_(1)= v_(2) l_(2) `.
If v be the FREQUENCY of TUNNING fork.
`(v - 5) 40= (v + 5) 39 `.
`rArr "" v = 395 ` Hz.
Hence the correct CHOICE is (c).


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