1.

A forms hcp lattice and B are occupying 1/3rd of tetrahedral voids, then the formula of compound is-

Answer»

AB
`A_(3)B_(2)`
`A_(2)B_(3)`
`AB_(4)`

SOLUTION :Let number of A atoms used in close PACKING = N
`therefore` Number of tetrahedral VOIDS = 2n
`therefore` Number of B atoms = `1/3xx2n=2/3n`
Ratio of A : B = 3 : 2
Then the formula of the compound is `A_(3)B_(2)`.


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