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A freely falling body, falling from a tower of heighth covers a distance h/2 in the last second of its motion The height of the tower is 10 ms^(-2)): |
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Answer» 58 m `x_(nth) u+(1)/(2) a(2n-1)implies(H)/(2)=0+(1)/(2)g(2n-1)` `implies h=g(2n-1)` Also `h=ut+(1)/(2)gn^(2) implies h=0+(1)/(2) gn^(2)` `:. (1)/(2)gn^(2)=g(2n-1) implies (1)/(2)n^(2)-2n +1=0` `n^(2) -4n+2=0 implies n+(4pmsqrt(16-4xx1xx2))/(2xx1)` Now `h=(1)/(2) gn^(2)=(1)/(2)xx10xx(3.414)^(2)=58 m` |
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