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    				| 1. | A fringe width of a certain interference pattern is `beta=0.002` cm What is the distance of 5th dark fringe centre?A. `1xx10^(-2)cm`B. `11xx10^(-2)cm`C. `13xx10^(-3)cm`D. `3.28xx10^(6)cm` | 
| Answer» Correct Answer - C The distance of 7th dark fringe from centre is given by `x_(n)=(2n+1)(lambda l)/(2d)` as n=6 for 7 th dark fringe So, `x_(7)=(13)/(2)(lambdaD)/(d) " as " (lambdaD)/(d)=beta` So, `x_(7)=((13)/(2))beta=(13)/(2)xx0.002=13xx10^(-3)cm` | |