1.

A fringe width of a certaininterference pattern is beta=0.002 cm. What is the distance of 5^(th) dark fringe from centre ?

Answer»

`1 xx 10^(-2) CM`
`11 xx 10^(-2) cm`
`1.1 xx 10^(-2) cm`
`3.28 xx 10^(6) cm`

Solution :`x_(N) = (2n+1)(lambda D)/(2D) = (2n+1)(BETA)/(2)`
For `5^(th)` dark FRINGE, n = 4
`x_(5) = (9)/(2) beta = (9)/(2) xx 2 xx 10^(-3)`
`= 9 xx 10^(-3) cm`


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