1.

A fuel cell is feed with 8 g of H_(2) and 40 g of O_(2) . How long would the fuel cell run to give a current of 5A?

Answer»

1608 minutes
8041 minutes
3217 minutes
12867 minutes

Solution :`H_(2)+(1)/(2)O_(2)RARR H_(2)O`
`2gH_(2)` REQUIRES 16g O
So, `8hH_(2)` will require = 64 g `O_(2)`
But OXYGEN given is 40 g, so oxygen is a limiting reagent.
So, `((40)/(32))xx4xx96500=5xx"t(sec)"`
`t=(40xx4xx96500)/(32xx5xx60)="1608 min"`


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