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A fuelcell develops an electrical potential from the combustion of butane at1 bar and 298 K C_4H_(10(g)) + 6.5O_(2(g)) to 4CO_(2(g)) + 5H_2O_((l)) , DeltaG^(0) = -2746 kUJ// mol |
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Answer» 4.74 V ` N = [4-(2.5)] xx 4 ` carbon atoms , n = 26 `DeltaG = -nFE^(0) - 2746 = -2.6 xx 96,500 xx E , E =(-2746)/(26 xx 96,500) = 1.07V` |
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