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A full wave rectifier delivers 50W to a load of 200Ω. If the ripple factor is 2%, calculate the AC ripple across the load.(a) 2V(b) 5V(c) 4V(d) 1VI had been asked this question in exam.This intriguing question originated from Full-wave Rectifier topic in chapter Application of Diodes of Electronic Devices & Circuits

Answer» CORRECT CHOICE is (a) 2V

To elaborate: We KNOW that, PDC=VDC^2/RL. So, VDC=(PDC*RL)^1/2=10000^1/2=100V.

 Here, ϒ=0.02

ϒ=VAC/VDC=VAC/100.So, VAC=0.02*100=2V.


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