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A full-wave rectifier used two diodes, the internal resistance of each diode may be assumed constant at 20Omega. The transformer r.m.s. secondary voltage from centre tap to each end of secondary is 50 V and load resistance is 980Omega Find: the r.m.s. value of load current |
| Answer» Solution :`r_f=20Omega,R_L=980Omega`MAX. a.c.voltage,`V_m=50xxsqrt2=70.7V`Max. LOAD CURRENT,`I_m=V_m/(r_f+R_L)=(70.7V)/((20+980)OMEGA)=70.7mA`R.M.S.value of load current is `I_(rms)=1_m/sqrt2=70.7/sqrt2=50mA` | |