A full wave rectifier uses load resistor of 1500Ω. Assume the diodes have Rf=10Ω, Rr=∞. The voltage applied to diode is 30V with a frequency of 50Hz. Calculate the AC power input.(a) 368.98mW(b) 275.2mW(c) 145.76mW(d) 456.78mWThe question was posed to me during a job interview.My question comes from Full-wave Rectifier in division Application of Diodes of Electronic Devices & Circuits

A full wave rectifier uses load resistor of 1500Ω. Assume the diodes

1.	A full wave rectifier uses load resistor of 1500Ω. Assume the diodes have Rf=10Ω, Rr=∞. The voltage applied to diode is 30V with a frequency of 50Hz. Calculate the AC power input.(a) 368.98mW(b) 275.2mW(c) 145.76mW(d) 456.78mWThe question was posed to me during a job interview.My question comes from Full-wave Rectifier in division Application of Diodes of Electronic Devices & Circuits
Answer» RIGHT option is (B) 275.2mW To explain I would SAY: The AC power input PIN=IRMS^2(RF+Rr). IRMS=Im/√2=Vm/(Rf+RL)√2=30/(1500+10)1.414=13.5mA So, PIN=(13.510-3)2*(1500+10)=275.2mW.

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