A full wave rectifier uses two diodes, the internalresistance of each diode may be assumed constant at 25Omega. The transformer r.m.s. secondary voltage from centre tap to each end of the secondary is 50V and land resistance is 975Omega. Find the mean load current

A full wave rectifier uses two diodes, the internalresistance of each

1.	A full wave rectifier uses two diodes, the internalresistance of each diode may be assumed constant at 25Omega. The transformer r.m.s. secondary voltage from centre tap to each end of the secondary is 50V and land resistance is 975Omega. Find the mean load current
Answer» `45xx10^(-3)A` `22.5xx10^(-3)A` `90xx10^(-3)A` `180xx10^(-3)A` Solution :`V_(0)=sqrt(2)V_(r.m.s)=sqrt2xx50=70.7` Max. load current, `I_(0)=(V_(0))/(r+R)` MEAN load current, `I_(m)=(2I_(0))/(pi)` `I_(r.m.s)=(I_(0))/(sqrt2)`

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A full wave rectifier uses two diodes, the internalresistance of each diode may be assumed constant at 25Omega. The transformer r.m.s. secondary voltage from centre tap to each end of the secondary is 50V and land resistance is 975Omega. Find the mean load current

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