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A full wave rectifier uses two diodes with a load resistance of 100Omega . Each diode is having negligible forward resistance. Find the efficiency of this full wave rectifier |
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Answer» SOLUTION :Forward resistance of the diode, `r_f =0 OMEGA `, LOAD resistance, `R_L = 100 Omega ,eta = ?` Efficiency of full wave RECTIFIER`eta =( 0.812R_L )/(r_f +R_L)` ` =( 0.812xx 100)/( 100 ) = 0.812` The percentage efficiency of the full wave rectifier=81.2% |
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