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A full wave rectifier uses two diodes with a load resistance of 100Omega. Each diode is having negligible forward resistance. Find the efficiency of this full wave rectifier.

Answer»

Solution :Forward resistance of the diode,
`r_(f)=0Omega,`Load resistance, `R_(L)=100Omega, ETA=?`
EFFICIENCY of full wave RECTIFIER
`eta=(0.812R_(L))/(r_(f)+R_(L))=(0.812xx100)/(100)=0.812`
The percentage efficiency of the full wave rectifier `= 81.2%`


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