A full wave rectifier with a load resistance of 5KΩ uses an inductor filter of 15henry. The peak value of applied voltage is 250V and the frequency is 50 cycles per second. Calculate the dc load current.(a) 0.7mA(b) 17mA(c) 10.6mA(d) 20mAThis question was posed to me in examination.I want to ask this question from Inductor Filters topic in portion Application of Diodes of Electronic Devices & Circuits

A full wave rectifier with a load resistance of 5KΩ uses an inductor

1.	A full wave rectifier with a load resistance of 5KΩ uses an inductor filter of 15henry. The peak value of applied voltage is 250V and the frequency is 50 cycles per second. Calculate the dc load current.(a) 0.7mA(b) 17mA(c) 10.6mA(d) 20mAThis question was posed to me in examination.I want to ask this question from Inductor Filters topic in portion Application of Diodes of Electronic Devices & Circuits
Answer» RIGHT ANSWER is (c) 10.6mA Easy explanation: For a RECTIFIER with an inductor filter, VDC=2Vm/π, Idc=VDC/RL=2Vm/RLπ IDC=2250/(3.1415*103)=10.6mA.

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