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A fully charged capacitor C with initial charge `q_0` is connected to a coil of self-inductance L at t=0. The time at which the energy is stored equally between the electric and the magnetic field isA. `pi/4sqrt(LC)`B. `2pisqrt(LC)`C. `sqrt(LC)`D. `pisqrt(LC)` |
Answer» Correct Answer - A During discharging of capacitor C through inductance L, let at any instant, charge in capacitor be Q. `thereforeQ=Q_0sinomegat` Maximum energy stored in capacitor-`1/2Q_0^2/C` Let at an instant t, the energy be stored equally between electric and magnetic field. Then energy stored in electric field at instant t is `1/2Q^2/C=1/2[1/2Q_0^2/C]`or,`Q^2=Q_0^2/2` or,`Q=Q_0/sqrt2`or,`sinomegat=Q_0/sqrt2` or,`omegat=pi/4`or,`t=pi/(4omega)=(pisqrt(LC))/4[becauseomega1/sqrt(LC)]` |
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