InterviewSolution
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InterviewSolution
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A fully charged capacitor C with initial charge `q_(0)` is connected to a coil of self inductance L at t=0. The time at which the energy is stored equally between the electric and the magnetic fields isA. `(pi)/(4)sqrt(LC)`B. `2pi sqrt(LC)`C. `sqrt(LC)`D. `pi sqrt(LC)` |
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Answer» Correct Answer - A As `omega^(2)=(1)/(LC)` or `omega=(1)/(sqrt(LC))` Maximum energy stored in capacitor `=(1)/(2)(Q_(0)^(2))/(C )` Let at any instant t, the energy be stored equally between electric and magnetic field. Then energy stored in electric field at instant t is `(1)/(2)(Q^(2))/(C )=(1)/(2)[(1)/(2)(Q_(0)^(@))/(C )]` or `Q^(2)=(Q_(0)^(2))/(2)` or `Q=(Q_(0))/(sqrt(2)) rArr Q_(0) cos omega t = (Q_(0))/(sqrt(2))` or `omega t=(pi)/(4)` or `t=(pi)/(4omega) = (pi)/(4xx(1//sqrt(LC)))=(pi sqrt(LC))/(4)` |
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