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A function f from the set of natural number to integers defined by `f(n)={{:(,(n-1)/(2),"when n is odd"),(,-(n)/(2),"when n is even"):}`A. neither one-one nor ontoB. one-one but not ontoC. one but not one-oneD. one-one and onto both |
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Answer» Correct Answer - D Clearly, range (f)=Z (Set of integers) So,f is onto We observe that distinct odd natural numbers are mapped to distinct non-negative integers and distinct even natural numbers are mapped to distinct negative integers. So, f is one-one Hence, f is both one-one and onto. |
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