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A fuse wire with radius of 0.2mm blows off with a current of 5 Amp. The fuse wire of same material, but of radius 0.3 mm will blow off with a current of 1) 5xx(3)/(2)" Amp" 2) (5sqrt3)/(2)" Amp" 3) 5sqrt((27)/(8))" Amp" 4) 5 Amp |
| Answer» Solution :`i^(2)propr^(3), (i_(1))/(i_(2))=((r_(1))/(r_(2)))^(3//2)=((0.1)/(0.3))^(3//2)""I,=5sqrt((27)/(8))" AMP"` | |