1.

A(g) + 3B(g) rarr 4C(g)Initially concentration of A is equal to that of B. The equilibrium concentrations of A and C are equal. Kc is :

Answer»

`0.08`
`0.8`
8
80

Solution :`{:(A,+,3B,hArr,4C),(a,,b,,0),((a-x),,(b-3x),,4X):}`
`K_(c)=([C]^(4))/([A][B]^(3))=(4x.4x.4x.4x)/((a-x)(b-3x))`
Given `a=b,a-x=4ximpliesa=5x=b`
`K_(c)=(4x.4x.4x.4x.)/((5x-x)(5x-3x))=(4x.4x.4x.4x)/(4x2x.2x2x)=8.`


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