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A gaivanometer of resistance 100 Omega contains 100 division. It gives a deflection of one division on passing a current of 10^(-4)A. Find the resistance to be connected to it, so that it becomes a coltmeter of range 10V. |
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Answer» `(500)/(9) alpha ` `10=0.01 (R+ 100) IMPLIES R =900 OMEGA` |
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