1.

A gaivanometer of resistance 100 Omega contains 100 division. It gives a deflection of one division on passing a current of 10^(-4)A. Find the resistance to be connected to it, so that it becomes a coltmeter of range 10V.

Answer»

`(500)/(9) alpha `
`500 alpha`
`(100)/(9) alpha `
`900 alpha`

Solution :`I _(G) =100xx10^(-4) =0.01 A`
`10=0.01 (R+ 100) IMPLIES R =900 OMEGA`


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