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A galvanic cell consists of a metallic zinc plate immersed in 0.1 M Zn (NO_(3))_(2) solution and metallic plate of lead in 0.02M Pb (NO_(3))_(2) solution.Calculte the emf of the cell. Write the chemical equation for the electrode reactions and represent the cell. (Given E_(Zn^(2+)//Zn)^(@)=-0.76V,E_(Pb^(2+),Pb)^(@)=-0.13V)

Answer»


ANSWER :0.6094V, `Zn+PB^(2+)TOZN^(2+)+Pb;Zn|Zn^(2+)(0.1M)||Pb^(2+)(0.02M)|Pb`


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