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A galvanometer coil has a resistance of 12 Omega and the meter shows full scale deflection for a current of 3 mA. How will you convert the meter into a voltmeter of range 0 to 18 V ? |
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Answer» Solution :Here `R_G = 12 OMEGA , I_g = 3 mA = 3 xx 10^(-3)A` and VOLTMETER.s rangeV = 18 V To convert galvanometer into a voltmeter of desired range, we should join a resistance R in SERIES with the galvonometer, where `R = V/(I_g) - R_G = 18/(3 xx 10^(-3)) - 12 = 6000 - 12 = 5988 Omega`. |
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