A galvanometer coil has a resistance of 12Omega and the metre shows full scale deflection for a current of 3 mA. How will you convert the metre into a voltmeter of range 0 to 18 V ?

A galvanometer coil has a resistance of 12Omega and the metre shows fu

1.	A galvanometer coil has a resistance of 12Omega and the metre shows full scale deflection for a current of 3 mA. How will you convert the metre into a voltmeter of range 0 to 18 V ?
Answer» Solution :1. Here, current capacity of galvanometer is, `I_(g)=3xx10^(-3)A` 2. Series resistance REQUIRED to CONVERT above galvanometer into voltmeter of voltage capacity V = 18 VOLT is, `R_(S)=V/I_(g)-G` `thereforeR_(S)=18/(3xx10^(-3))-12=5988Omega` THUS, we should connect `5988Omega` resistance in series with above galvanometer and then we should CALIBRATE its scale from 0 to 18 volt in order to prepare required voltmeter.

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A galvanometer coil has a resistance of 12Omega and the metre shows full scale deflection for a current of 3 mA. How will you convert the metre into a voltmeter of range 0 to 18 V ?

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