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A galvanometer coil has a resistance of 15Omega and the metre shows full scale deflection for acurrent of 4 mA. How will you convert the metre into an ammeter of range 0 to 6 A ? |
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Answer» Solution :1. Here, current capacity of GALVANOMETER is, `I_(g)=4xx10^(-3)A` 2. SHUNT resistance required to convert above galvanometer into an ammeter of current capacity I = 6 A is, `S=((4xx10^(-3))(15))/((6)-(4xx10^(-3)))` `thereforeS=0.01Omega` 3. THUS, we should connect `0.01Omega` resistance in parallel with above galvanometer and then we should calibrate its scale from 0 to 6 A in order to prepare required ammeter. |
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