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A galvanometer gives full scale deflection with 0.006 A current. By connecting it to a 4990 Omegaresistance, it can be converted into a voltmeter of range 0-30 V. If connected to a(2n)/249 Omega resistance, it becomes an ammeter of range 0-1.5AThe value of n is |
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Answer» Solution :`i_g(G+4990)=V IMPLIES 6/1000(G+4990)=30 i_g=4990 Omega` `G+4990=30000/6=5000 implies G=10 Omega` `V_(ab)=V_(cd) implies j_gG=(1.5-j_g)S` `6/1000 times 10=(1.5-6/1000)S` `S=60/1494=(2N)/249 implies n=(249 times 30)/1494=2490/498=5` 
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