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A galvanometer has a coil of resistance 100Omega andgives a full scale deflection for 30 volt range, the resistance required to be added will be |
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Answer» `900Omega` RESISTANCE of galvanometer, `G=100Omega` Current for full SCALE deflection, `l_(g)=30mA=30xx10^(-3)A` Range of voltmeter, V=30V To convert the galvanometer into an voltmeter of a given range, a resistance R is connected in series with it.  From figure, `V=l_(g)(G+R)` or `R=(V)/(l_(g))-G=(30)/(30xx10^(-3))-100Omega` `=1000-100=900Omega` |
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