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| 1. |
A galvanometer has a resistance G and requires a current I_(g) for full scale deflection. How do you convert it into (i) an ammeter? (ii) a voltmeter? |
| Answer» SOLUTION :(a) `S=(I_(G)G)/(I-I_(g))" i.e., " I propto I_(g)` where 'S' is the SHUNT RESISTANCE connected in parallel to the galvanometer and (b) `R=V/I_(g)-G " i.e., " I_(g) propto V` where 'R' is a resistance connected in series with the galvanometer. | |