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A galvanometer having a coil of resistance 12 Ωgives full scale deflection for a current of 4 mA. How can it be converted into a voltmeter of range 0 to 24V. |
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Answer» Solution :`G= 12 OMEGA I_(g) =4A ,V =24 V` `R=(I)/(I_(g))-G` =6000-12 =5988 R=5988 `omega`By CONNECTING this high resistance in SERIES with the GALVANOMETER we can convert galvanometer into a voltmeter. |
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