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A galvanometer having a resistance of 20 ohm and capable of carrying a maximum current of 40 m A is to be converted into an ammeter of range `0-5` A. What is the resistance needed?A. `1.6Omega` in parallelB. `0.16Omega` in parallelC. `16.1Omega` in parallelD. None of these |
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Answer» Correct Answer - B `S=(I_g .G)/(I-I_g)` `S=(40xx10^-3xx20)/(5-0.040)=0.16Omega` . |
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