1.

A galvanometer of coil resistance 100Omegais connected to a shunt of resistance 10 Omega. The current through the galvanometer is i_1 , the current through the shunt is i_2and the total current into the combination is i_3 , then the ratioi_1 : i_2 : i_3is

Answer»

`1:10:11`
`10:1:11 `
`11:10:1`
`10:11:1`

SOLUTION :`IG = (S)/(G+S) (I)`


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