1.

A galvanometer of resistance 20Omega is shunted by a 2Omega resistor. What part of the main current flows through the galvanometer ?

Answer»

SOLUTION :`(i_(g))/i=G/(G+S)`. Given `G = 20Omega , S = 2OMEGA`
`THEREFORE(i_(g))/i=2/22=1/11,1/11`TH part of CURRENT is passing through galvanometer.


Discussion

No Comment Found

Related InterviewSolutions