Saved Bookmarks
| 1. |
A galvanometer of resistance 20Omega is shunted by a 2Omega resistor. What part of the main current flows through the galvanometer ? |
|
Answer» SOLUTION :`(i_(g))/i=G/(G+S)`. Given `G = 20Omega , S = 2OMEGA` `THEREFORE(i_(g))/i=2/22=1/11,1/11`TH part of CURRENT is passing through galvanometer. |
|