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A galvanometer of resistance 5 Omega can be converted into a voltmeter of range 0 - V voltmeter of range 0 - V volts by connecting a resistance R Omega in series with it. How much resistance will be required to charge its range to 0 - V/2 volts? |
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Answer» Solution :As GALVANOMETER of resistance G can be converted into a voltmeter of range 0- V volts by adding a SERIES resistance `R Omega`, hence `R = V/(I_g) - G implies I_(g) = V/(R + G)` Let a resistance `R. Omega` be joined in series with galvanometer to convert it into a voltmeter of range `V. = V/2` volts , then `R. = (V.)/(I_g) - G = (V//2)/(V//R + G) - G = (R + G)/(2) - G = (R - G)/(2)`. |
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