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A galvanometer of resistance 95Omega , shunted by a resistance of 5 ohm gives a deflection of 50 divisions when joined in series with a resistance of 20 kOmega and a 2 volt accumulator. What is the current sensitivity of the galvanometer (in div / muA )? |
Answer» Solution : In accordance with given problem, the situation is depicted by the CIRCUIT diagram in fig. As here `20 KOMEGA` is much greater than the resistance of shunted galvanometer ( < 5`Omega` ), the current in the circuit will be `I=2/(20xx10^(3))=10^(-4)A=100muA` and as this current PRODUCES DEFLECTION of 50 divisions in the galvanometer `CS=(theta)/I=(50"div")/(100muA)=1/2("div")/(MUA)` |
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